Question

6) Бассейн наполняется водой с по- мощью двух труб. Одна труба заливает воду со скоростью 20 м3/ч, вторая — 30 м3/ч. Через сколько часов объём воды в бассейне достигнет 300 м? ​

Answer 1

Решение: 300:(20+30) = 6 (ч)
Ответ: за 6 часов

Answer 2

Problem Analysis

We are given that a pool is being filled with water using two pipes. One pipe fills the pool at a rate of 20 m³/h, while the other pipe fills the pool at a rate of 30 m³/h. We need to determine how many hours it will take for the volume of water in the pool to reach 300 m³.

Solution

To solve this problem, we can calculate the combined rate at which the two pipes fill the pool and then use that rate to determine the time it takes to reach a volume of 300 m³.

Let's calculate the combined rate of the two pipes: - Pipe 1 fills the pool at a rate of 20 m³/h. - Pipe 2 fills the pool at a rate of 30 m³/h.

The combined rate of the two pipes is the sum of their individual rates: Combined rate = Rate of Pipe 1 + Rate of Pipe 2

Now, let's calculate the combined rate: Combined rate = 20 m³/h + 30 m³/h = 50 m³/h

The combined rate of the two pipes is 50 m³/h.

To determine the time it takes to reach a volume of 300 m³, we can use the formula: Time = Volume / Rate

Substituting the values: Time = 300 m³ / 50 m³/h

Simplifying the expression: Time = 6 hours

Therefore, it will take 6 hours for the volume of water in the pool to reach 300 m³.

Answer: The volume of water in the pool will reach 300 m³ in 6 hours.