Question

( х+7)(х-1)≥0 Попалось на ОГЭ, там должны быть парабола?

Answer 1

Ответ:x+7>0

x<-7

x-1>0

x>1

x принадлежит (-бесконечность,-7],[1,+бесконечность )

Пошаговое объяснение:

Answer 2

Quadratic Inequality: (x+7)(x-1)≥0

To solve the quadratic inequality (x+7)(x-1)≥0, we need to find the values of x that satisfy the inequality.

To do this, we can use the concept of the sign chart or the zero-product property. Let's use the zero-product property in this case.

The zero-product property states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero.

In this case, we have (x+7)(x-1)≥0. To find the values of x that satisfy this inequality, we need to find the values of x for which the product (x+7)(x-1) is greater than or equal to zero.

To find these values, we can set each factor equal to zero and solve for x:

x+7=0 => x=-7

x-1=0 => x=1

So, we have two critical points: x=-7 and x=1.

Now, we can create a sign chart to determine the intervals where the product (x+7)(x-1) is positive or negative.

| Interval | (x+7) | (x-1) | (x+7)(x-1) | |------------|--------|--------|-------------| | x<-7 | - | - | + | | -71 | + | + | + |

From the sign chart, we can see that the product (x+7)(x-1) is positive in the intervals x<-7 and x>1, and negative in the interval -7

Therefore, the solution to the inequality (x+7)(x-1)≥0 is x≤-7 or x≥1.

In conclusion, the values of x that satisfy the inequality (x+7)(x-1)≥0 are x≤-7 or x≥1.

Note: The question mentioned that this problem was encountered on an exam. However, it is important to note that the answer provided here is a general solution to the quadratic inequality and may not be specific to the context of the exam question. It is always recommended to refer to the specific instructions and context provided in the exam question.