Question

Розв'яжи задачу за допомогою рівняння: В першій коробці цукерок було в 4 рази більше, ніж у другій. Коли з першої коробки взяли 7 цукерок, а у другу коробку поклали 20 цукерок, то в обох коробках стало порівну. Скільки цукерок було в кожній коробці?​

Answer 1

Ответ:

Пошаговое объяснение:

х цукерок - у ІІ коробці

4х цукерок - у І коробці

150%=1,5

4х-8=(х+8)*1,5

4х-8=1,5х+12

2,5х=20

х=8(цукерок) - було у ІІ коробці

8*4=32(цукерки) - було у І коробці

Answer 2

To solve this problem, let's assign variables to the number of candies in each box. Let's say the number of candies in the first box is represented by 'x', and the number of candies in the second box is represented by 'y'.

According to the problem, the number of candies in the first box is 4 times more than the number of candies in the second box. So we can write the equation:

x = 4y

Next, we are given that when 7 candies are taken from the first box and 20 candies are added to the second box, the number of candies becomes equal in both boxes. Mathematically, we can write this as:

(x - 7) = (y + 20)

Now we can solve these two equations simultaneously to find the values of x and y.

Substituting the value of x from the first equation into the second equation, we get:

(4y - 7) = (y + 20)

Simplifying this equation, we have:

4y - y = 20 + 7

3y = 27

Dividing both sides of the equation by 3, we find:

y = 9

Now, substituting the value of y back into the first equation, we can find the value of x:

x = 4y = 4 * 9 = 36

Therefore, there were 36 candies in the first box and 9 candies in the second box.

Please let me know if you need any further assistance!