Question

В першій цистерні у 5 разів більше води, ніж у другій. Скільки вод У першій цистерні, якщо у другій на 8 т води менше, ніж у першій? срочно!!!​

Answer 1

Ответ:

10т

Пошаговое объяснение:

Х - воды во второй цистерн, в первой тогда 5х

5х-8=х

4х=8

Х=2

В первой цистерн 10т

Answer 2

5x-8=x

5x-x=8

4x=8

x=8/4

x=2

2×5=10t

Answer 3

Problem Analysis

We are given two tanks, and the first tank contains 5 times more water than the second tank. Additionally, the second tank has 8 tons less water than the first tank. We need to find the amount of water in the first tank.

Solution

Let's assume the amount of water in the second tank is x tons. According to the problem, the first tank contains 5 times more water than the second tank, so the amount of water in the first tank is 5x tons.

We are also given that the second tank has 8 tons less water than the first tank. This can be expressed as:

5x - 8 = x

To find the value of x, we can solve this equation:

4x = 8

Dividing both sides of the equation by 4, we get:

x = 2

Therefore, the amount of water in the first tank is:

5x = 5 * 2 = 10 tons

So, there are 10 tons of water in the first tank.

Answer

The first tank contains 10 tons of water.

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