
Определите по тригонометрическрму кругу sinL, cosL, если L равно
19π/3;9π/4;-25π/2;-88π;13π/6;25π/4;-28π/3;-23π/6;15π/2;7πСРОЧНО ПОМОГИТЕ!!ЗАРАНЕЕ СПАСИБО!

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Trigonometric Circle and Values of sin(L) and cos(L)
To determine the values of sin(L) and cos(L) for the given angles L, we can use the unit circle and the trigonometric definitions of sine and cosine.
The unit circle is a circle with a radius of 1 unit, centered at the origin of a coordinate plane. It is used to define the values of sine and cosine for any angle.
The trigonometric definitions of sine and cosine are as follows:
- Sine (sin): In a right triangle, the sine of an angle is defined as the ratio of the length of the side opposite the angle to the length of the hypotenuse. - Cosine (cos): In a right triangle, the cosine of an angle is defined as the ratio of the length of the adjacent side to the length of the hypotenuse.
Using the unit circle, we can determine the values of sin(L) and cos(L) for the given angles L.
Values of sin(L) and cos(L) for the given angles L:
1. L = 19π/3: - sin(19π/3) = -√3/2 [[1]] - cos(19π/3) = -1/2 [[1]]
2. L = 9π/4: - sin(9π/4) = -√2/2 [[2]] - cos(9π/4) = √2/2 [[2]]
3. L = -25π/2: - sin(-25π/2) = -1 [[3]] - cos(-25π/2) = 0 [[3]]
4. L = -88π: - sin(-88π) = 0 [[4]] - cos(-88π) = 1 [[4]]
5. L = 13π/6: - sin(13π/6) = -1/2 [[5]] - cos(13π/6) = √3/2 [[5]]
6. L = 25π/4: - sin(25π/4) = √2/2 [[6]] - cos(25π/4) = √2/2 [[6]]
7. L = -28π/3: - sin(-28π/3) = √3/2 [[7]] - cos(-28π/3) = 1/2 [[7]]
8. L = -23π/6: - sin(-23π/6) = 1/2 [[8]] - cos(-23π/6) = √3/2 [[8]]
9. L = 15π/2: - sin(15π/2) = 1 [[9]] - cos(15π/2) = 0 [[9]]
10. L = 7π: - sin(7π) = 0 [[10]] - cos(7π) = -1 [[10]]
I hope this helps! Let me know if you have any further questions.


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