Question

2m+3=19 2(x-3)=36 4(m+1)+11=31

Answer 1

2m+3=19
2m=19-3
2m=16
m=16:2
m=8
Ответ: m=8
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2(х-3)=36
2х-6=36
2х=36+6
2х=42
х=42:2
х=21
Ответ: х=21
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4(m+1)+11=31
4m+4+11=31
4m=31-11-4
4m=16
m=16:4
m=4
Ответ:m=4

Answer 2

To solve these equations for the variables m and x, follow these steps:

1. Solve the equation 2m + 3 = 19 for m:

   Subtract 3 from both sides of the equation: 2m = 19 - 3 2m = 16

   Now, divide both sides by 2 to isolate m: m = 16 / 2 m = 8

2. Solve the equation 2(x - 3) = 36 for x:

   First, distribute the 2 on the left side of the equation: 2x - 6 = 36

   Add 6 to both sides of the equation: 2x = 36 + 6 2x = 42

   Now, divide both sides by 2 to isolate x: x = 42 / 2 x = 21

3. Solve the equation 4(m + 1) + 11 = 31 for m:

   First, distribute the 4 on the left side of the equation: 4m + 4 + 11 = 31

   Combine the constants on the left side (4 + 11): 4m + 15 = 31

   Subtract 15 from both sides of the equation: 4m = 31 - 15 4m = 16

   Now, divide both sides by 4 to isolate m: m = 16 / 4 m = 4

So, the solutions for the variables are: m = 8 x = 21 m = 4