Question

Ə) 3/x-2/y=132/x+7/y=-8 ​

Answer 1

ху+7у=-8

ху2=-8-7

ху2=-1

-1+7=8

${y}^{2}$

Answer 2

It looks like you have a system of two linear equations with two variables, x and y. You can solve this system using various methods, such as substitution or elimination. In this case, I'll use the elimination method to solve the system:

The given equations are:

1. 3/x - 2/y = 13
2. 2/x + 7/y = -8

We can start by multiplying both sides of each equation by the least common multiple (LCM) of the denominators to get rid of the fractions:

LCM(x, y) = xy

For the first equation, we'll multiply by xy:

1. xy(3/x) - xy(2/y) = 13xy 3y - 2x = 13xy

For the second equation, we'll also multiply by xy:

2. xy(2/x) + xy(7/y) = -8xy 2y + 7x = -8xy

Now we have the system of equations:

1. 3y - 2x = 13xy
2. 2y + 7x = -8xy

We can start by isolating one of the variables, and then substitute that into the other equation. Let's isolate x from the first equation:

3y - 2x = 13xy

3y = 13xy + 2x

3y - 13xy = 2x

x = (3y - 13xy)/2

Now, we can substitute this expression for x into the second equation:

2y + 7x = -8xy

2y + 7((3y - 13xy)/2) = -8xy

Now, we'll simplify the equation:

2y + (21y - 91xy) = -8xy

Combine like terms:

23y - 91xy = -8xy

Now, let's isolate y:

23y = -8xy + 91xy

23y = 83xy

y = (83xy)/23

Now we have expressions for both x and y in terms of each other. We can solve for their values by setting them equal to each other since they are both equal to each other:

(3y - 13xy)/2 = (83xy)/23

Now, you can solve for the values of x and y. The actual numerical values for x and y will depend on the specific values of x and y that satisfy this equation.