Question

1/10+7/20-2/40= 17/20-3/10-11/60= 3/20+7/10-3/40= 9/40+3/4-19=

Answer 1

1/10+7/20-2/40= 17/20-3/10-11/60= 3/20+7/10-3/40= 9/40+3/4-19= -721/40

Answer 2

Let's solve each expression step by step:

1. $\frac{1}{10} + \frac{7}{20} - \frac{2}{40}$: First, let's find a common denominator, which is 40: $\frac{4}{40} + \frac{14}{40} - \frac{1}{40} = \frac{17}{40}$

2. $\frac{17}{20} - \frac{3}{10} - \frac{11}{60}$: Let's find a common denominator, which is 60: $\frac{51}{60} - \frac{18}{60} - \frac{11}{60} = \frac{22}{60}$ (or simplifying, $\frac{11}{30}$)

3. $\frac{3}{20} + \frac{7}{10} - \frac{3}{40}$: Let's find a common denominator, which is 40: $\frac{6}{40} + \frac{28}{40} - \frac{3}{40} = \frac{31}{40}$

4. $\frac{9}{40} + \frac{3}{4} - 19$: Let's convert $19$ to have a denominator of $40$ (which is the common denominator): $\frac{9}{40} + \frac{30}{40} - \frac{760}{40} = \frac{-721}{40}$ (or as a mixed number, $-18 \frac{1}{40}$)

Answer 3

Let's solve each expression step by step:

1. $\frac{1}{10} + \frac{7}{20} - \frac{2}{40}$ First, let's find a common denominator, which is 40: $\frac{4}{40} + \frac{14}{40} - \frac{1}{40} = \frac{17}{40}$

2. $\frac{17}{20} - \frac{3}{10} - \frac{11}{60}$ Let's find a common denominator, which is 60: $\frac{51}{60} - \frac{18}{60} - \frac{11}{60} = \frac{51 - 18 - 11}{60} = \frac{22}{60} = \frac{11}{30}$

3. $\frac{3}{20} + \frac{7}{10} - \frac{3}{40}$ Let's find a common denominator, which is 40: $\frac{6}{40} + \frac{28}{40} - \frac{3}{40} = \frac{31}{40}$

4. $\frac{9}{40} + \frac{3}{4} - 19$ Let's first convert 19 to a fraction with a denominator of 40: $\frac{9}{40} + \frac{30}{40} - \frac{760}{40} = - \frac{721}{40}$