Question

58-20+C=40, 14:C=2, C-(20+9)=60​

Answer 1

1) 38+с=40

с=40-38

с=2

2) с=14:2

с=7

3) с-29=60

с=60+29

с=89

Answer 2

58-20+с=40 14:с=2

38+с=40 с=14:2

с=40-38 с=7

с=2

С-(20+9)=60

С-29=60

с=60+29

с=89

Answer 3

Let's solve each of these equations one by one:

1. 58 - 20 + C = 40

First, perform the subtraction and simplify the equation:

C + 38 = 40

Now, isolate the variable C by subtracting 38 from both sides of the equation:

C = 40 - 38 C = 2

So, C = 2 is the solution to the first equation.

2. 14:C = 2

To solve for C in this equation, you can multiply both sides by 14:

14 * (14:C) = 14 * 2

This simplifies to:

C = 28

So, C = 28 is the solution to the second equation.

3. C - (20 + 9) = 60

First, perform the addition inside the parentheses:

C - 29 = 60

Now, isolate the variable C by adding 29 to both sides of the equation:

C = 60 + 29 C = 89

So, C = 89 is the solution to the third equation.

To recap:

1. C = 2
2. C = 28
3. C = 89