Question

(3 1/6-а)+(2 1/4-b) пжж​

Answer 1

Ответ:

65/12-a-b

Пошаговое объяснение:

(19/6-a)+(9/4-b)

19/6-a+9/4-b

65/12-a-b

Answer 2

To simplify the given expression $(3 \frac{1}{6} - a) + (2 \frac{1}{4} - b)$, you can first simplify the fractions and then perform the addition and subtraction.

$\frac{3 \times 6 + 1}{6} = \frac{19}{6}$, and $\frac{2 \times 4 + 1}{4} = \frac{9}{4}$.

Now, the expression becomes $\left( \frac{19}{6} - a \right) + \left( \frac{9}{4} - b \right)$.

To add or subtract fractions, you need a common denominator. The least common multiple of 6 and 4 is 12.

So, $\frac{19}{6} = \frac{19 \times 2}{6 \times 2} = \frac{38}{12}$, and $\frac{9}{4} = \frac{9 \times 3}{4 \times 3} = \frac{27}{12}$.

Now, the expression becomes $\left( \frac{38}{12} - a \right) + \left( \frac{27}{12} - b \right)$.

Now, you can combine like terms:

$\frac{38 - 12a + 27 - 12b}{12}$.

Simplifying further:

$\frac{65 - 12a - 12b}{12}$.

So, the simplified expression is $\frac{65 - 12a - 12b}{12}$.