Question

2.2. 18-3y - 3y <= 0 4y > 12

Answer 1

Ответ:

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Пошаговое объяснение:

Answer 2

To solve the inequality 2.2 - 18y - 3y ≤ 0 and find when 4y > 12, you can follow these steps:

Step 1: Simplify the first inequality: 2.2 - 18y - 3y ≤ 0

Combine the like terms on the left side: 2.2 - 21y ≤ 0

Step 2: Now, solve for y by isolating y on one side of the inequality:

Subtract 2.2 from both sides to move the constant to the right side: -21y ≤ -2.2

Step 3: Divide both sides by -21. Since you're dividing by a negative number, you need to reverse the inequality sign:

y ≥ -2.2 / -21 y ≥ 0.10476190476 (approximately)

So, the solution for the first inequality is y ≥ 0.1048 (rounded to 4 decimal places).

Step 4: Now, let's solve the second inequality:

4y > 12

Divide both sides by 4 to isolate y: y > 12 / 4 y > 3

The solution for the second inequality is y > 3.

So, the combined solution for both inequalities is: y ≥ 0.1048 and y > 3

However, since these two inequalities have different solutions, you can express the solution set as two separate intervals:

1. y ≥ 0.1048 (for the first inequality)
2. y > 3 (for the second inequality)