Question

1/7*(2x-10)=1/2*(3x+5)​

Answer 1

1/7*(2x-10)=1/2*(3x+5)

2х-10=7/2*(3х+5)

2х-10=21/2х+35/2

4х-20=21х+35

4х-21х=35+20

-17х=55

х=-55/17=-3 4/17

Answer 2

Пошаговое объяснение:

1/7(2х-10)=1/2(3х+5)

2х-10=1/2:1/7(3х+5)

2х-10=7/2(3х+5)

2х-10=21х/2+35/2

4х-20=21х+35

4х-21х=35+20

-17х=55

Х= - 55/17= - 3 4/17

Answer 3

To solve for the value of "x" in the equation:

(1/7) * (2x - 10) = (1/2) * (3x + 5)

You can start by getting rid of the fractions by multiplying both sides of the equation by the least common multiple (LCM) of 7 and 2, which is 14. This will clear the fractions:

14 * [(1/7) * (2x - 10)] = 14 * [(1/2) * (3x + 5)]

Now, simplify both sides:

2 * (2x - 10) = 7 * (3x + 5)

Now distribute the constants on the left and right sides of the equation:

4x - 20 = 21x + 35

Next, isolate the "x" terms on one side of the equation and the constant terms on the other side. You can do this by subtracting 4x from both sides and subtracting 35 from both sides:

4x - 21x = 35 + 20

-17x = 55

Now, divide both sides by -17 to solve for "x":

x = 55 / -17

x ≈ -3.235

So, the solution for the equation is approximately x ≈ -3.235.