Question

19 28/32 – (m + 2) = 12 15/32

Answer 1

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Answer 2

To solve for "m" in the equation 19 28/32 - (m + 2) = 12 15/32, you can follow these steps:

Step 1: Convert the mixed numbers to improper fractions. 19 28/32 = 19 + 28/32 = 19 + 7/8 = 19 7/8 12 15/32 = 12 + 15/32 = 12 + 15/32 = 12 15/32

Now, the equation becomes: 19 7/8 - (m + 2) = 12 15/32

Step 2: Subtract 19 7/8 from both sides of the equation to isolate (m + 2): (m + 2) = 12 15/32 - 19 7/8

Step 3: Subtract the fractions on the right-hand side. To do this, you need a common denominator, which is 32 * 8 = 256.

12 15/32 - 19 7/8 = (12 * 8 + 15) / 32 - (19 * 32 + 7) / 32 = (96 + 15) / 32 - (608 + 7) / 32 = (111/32) - (615/32)

Now, subtract the fractions: (m + 2) = (111/32) - (615/32) (m + 2) = (-504/32)

Step 4: Simplify the right-hand side: (m + 2) = (-504/32)

Now, divide both sides by 32 to solve for "m": (m + 2) / 32 = (-504/32) / 32 (m + 2) / 32 = -504/1024

Simplify the right-hand side: (m + 2) / 32 = -63/128

Step 5: Finally, isolate "m" by subtracting 2 from both sides: (m + 2) / 32 - 2 = -63/128 - 2

(m + 2) / 32 = (-63/128) - (2 * 128/128) (m + 2) / 32 = (-63 - 256) / 128 (m + 2) / 32 = -319/128

Now, multiply both sides by 32 to solve for "m": m + 2 = (-319/128) * 32 m + 2 = -8

Subtract 2 from both sides to get the final answer for "m": m = -8 - 2 m = -10

So, the solution for the equation is: m = -10