Question

J) −(6x + 5) + 2 ≤ 6k)7-3(21-x)≥10l)2(x+6)-6≤-3​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

Let's solve each of these inequalities step by step:

J) -(6x + 5) + 2 ≤ 6 First, simplify the left side of the inequality: -6x - 5 + 2 ≤ 6

Now, combine like terms: -6x - 3 ≤ 6

Next, add 3 to both sides of the inequality to isolate the term with x: -6x - 3 + 3 ≤ 6 + 3 -6x ≤ 9

Now, divide both sides by -6, remembering to reverse the inequality sign since you're dividing by a negative number: x ≥ -9/6 x ≥ -3/2

So, the solution to J) is x ≥ -3/2.

K) 7 - 3(21 - x) ≥ 10 First, simplify the expression inside the parentheses: 7 - 3(21 - x) ≥ 10 7 - 63 + 3x ≥ 10

Now, combine like terms: -56 + 3x ≥ 10

Add 56 to both sides of the inequality to isolate the term with x: -56 + 56 + 3x ≥ 10 + 56 3x ≥ 66

Finally, divide both sides by 3: 3x/3 ≥ 66/3 x ≥ 22

So, the solution to K) is x ≥ 22.

L) 2(x + 6) - 6 ≤ -3 First, distribute the 2 on the left side of the inequality: 2x + 12 - 6 ≤ -3

Now, combine like terms: 2x + 6 ≤ -3

Subtract 6 from both sides of the inequality to isolate the term with x: 2x + 6 - 6 ≤ -3 - 6 2x ≤ -9

Finally, divide both sides by 2: 2x/2 ≤ -9/2 x ≤ -9/2

So, the solution to L) is x ≤ -9/2.