Question

1) (14x+7)(2,1-0,3x)=0

Answer 1

Ответ:

Пошаговое объяснение:

14x+7=0 ; 2,1-0,3x=0 решить такую систему

14х+7=0

14х=-7

Х=-7:14

Х=-1/2

2,1-0,3х=0

-0,3х=-2,1

Х=-2,1:(-0,3)

Х=7

Два решения: х=-1/2; х=7

Answer 2

To solve the equation $(14x+7)(2.1-0.3x) = 0$, you can use the zero-product property, which states that if the product of two factors equals zero, then at least one of the factors must be zero. So, you set each factor equal to zero and solve for $x$:

1. Set $14x+7$ equal to zero: $14x+7 = 0$

Subtract 7 from both sides: $14x = -7$

Divide by 14: $x = \frac{-7}{14} = -\frac{1}{2}$

2. Set $2.1-0.3x$ equal to zero: $2.1 - 0.3x = 0$

Subtract 2.1 from both sides: $-0.3x = -2.1$

Divide by -0.3: $x = \frac{-2.1}{-0.3} = 7$

So, there are two solutions to the equation: $x = -\frac{1}{2}$ and $x = 7$.