Question

4) 2y + 3x² - 3 = 0;​

Answer 1

Ответ:

3x-y=3

3х-2у=0

3х-3=y

3х-2 (3х-3)=0

3х-6х+6=0

-3х=-6

x=-6 :-3

х=2

Подставим х=2 в у=3х-3

y=3*2-3

y=6-3

y=3

Answer 2

The equation you've provided is:

2y + 3x² - 3 = 0

This is a quadratic equation in two variables, x and y. To solve for one variable in terms of the other, you can rearrange the equation. In this case, let's solve for y in terms of x:

2y = -3x² + 3

Now, divide both sides by 2 to isolate y:

y = (-3x² + 3)/2

So, the solution for y in terms of x is:

y = (-3x² + 3)/2