Question

F(3-2x)=[4-x] f(2-x)=3x+1/2x-3 f(1-2x=2x+3/3-x f(x+3)=2 корень 4-x f(2-x)=3 корень x+5

Answer 1

F(1-2x)=2x +3/3-x
F(1-2x) =2 x + 1-x
F(1-2x)= x+1

Answer 2

It looks like you've provided a series of equations involving a function f(x) and asked for solutions or conditions. Let's go through them one by one:

1. $f(3-2x) = 4 - x$

   To solve for x, we'll substitute $3 - 2x$ in place of $x$ in the right-hand side:

   $f(3 - 2x) = 4 - (3 - 2x) = 4 - 3 + 2x = 2x + 1$

   So, we have $f(3 - 2x) = 2x + 1$.

2. $f(2 - x) = \frac{3x + 1}{2x - 3}$

   This equation relates $f(2 - x)$ to $x$ using a rational function. This is an equation that defines $f(x)$, but it doesn't provide a specific solution for $x$.

3. $f(1 - 2x) = \frac{2x + 3}{3 - x}$

   Similar to the previous equation, this one defines $f(x)$ in terms of $x$, but doesn't give a specific solution for $x$.

4. $f(x + 3) = 2\sqrt{4 - x}$

   This equation relates $f(x + 3)$ to $x$ using a square root function. This is another equation that defines $f(x)$, but doesn't provide a specific solution for $x$.

5. $f(2 - x) = \sqrt{x + 5}$

   Similar to the previous equations, this one defines $f(x)$ in terms of $x$ but doesn't give a specific solution for $x$.

If you're looking for numerical solutions, you would need more information about the function $f(x)$ itself. If you have a specific function in mind, please provide it and I can help you with solving these equations.