Question

((Sin(π/4)+cos(3π/2))*tg(π/3))/(ctg(π/6)-ctg (π/2))

Answer 1

K это корень
((k2/2 + 0)*k3)/(k3-0)=k6/2 * 1/k2 =k2/2= sin(п/4)

Answer 2

To simplify the given expression, let's first evaluate each trigonometric function step by step:

1. sin(π/4) = √2 / 2
2. cos(3π/2) = 0 (cosine is zero at 3π/2)
3. tan(π/3) = √3
4. cot(π/6) = √3
5. cot(π/2) = 0 (cotangent is zero at π/2)

Now, let's substitute these values into the expression:

((√2/2 + 0) * √3) / (√3 - 0)

Simplifying further:

(√2 * √3) / √3

Since √3/√3 = 1:

√2

So, the simplified expression is √2.