Question

В 3-Х вагонах едет 100 пассажиров. В 1-ом и 2-ом 66 пассажиров, во 2-ом и 3-ем вагонах 69 пассажиров. Сколько в каждом вагоне пассажиров?

Answer 1

1) 66+69 = 135 (чел)  едет в первом, удвоенном втором и третьем вагонах
2) 135 - 100 = 35 (чел) едет во втором вагоне
3) 66-35 = 31 чел  - едет в первом вагоне
4) 69 - 35 = 34 чел  - едет в третьем вагоне

Answer 2

1)100-66=34 в третьем
2)69-34=35 во втором
3)66-35=31 в первом

Answer 3

Let's use algebra to solve the problem. Let's assume that the number of passengers in the first wagon is x, in the second wagon is y, and in the third wagon is z.

We have three equations based on the information given:

1. In the 1st and 2nd wagons, there are 66 passengers: x + y = 66
2. In the 2nd and 3rd wagons, there are 69 passengers: y + z = 69
3. In total, there are 100 passengers: x + y + z = 100

Now we can solve this system of equations to find the values of x, y, and z.

First, let's rearrange the equations for clarity:

1. x + y = 66
2. y + z = 69
3. x + y + z = 100

Now, let's solve the system of equations. We can use the first equation to express x in terms of y:

1. x = 66 - y

Now substitute this value of x in the third equation:

3. (66 - y) + y + z = 100 66 + z = 100 z = 100 - 66 z = 34

Now, we have the value of z. Let's find y by using the second equation:

2. y + 34 = 69 y = 69 - 34 y = 35

Now we have the values of y and z. Finally, let's find x using the first equation:

1. x + 35 = 66 x = 66 - 35 x = 31

So, there are 31 passengers in the 1st wagon, 35 passengers in the 2nd wagon, and 34 passengers in the 3rd wagon.