Question

Для функции f(x)= x^3-3x^2-2.Найти f(0),f(1),f(-3),f(5).

Answer 1

 f(x)= x^3-3x^2-2

x=0   f(x)= 0-0-2=-2
x=1   f(x)=1-3-2=-4
x=-3   f(x)= -27-27-2=-56
x=5     f(x)= 125-75-2=48

Answer 2

To find the values of the function $f(x) = x^3 - 3x^2 - 2$ for the given values of $x$, we simply substitute each value into the function and compute the result. Here are the calculations:

1. $f(0)$: $f(0) = 0^3 - 3 \cdot 0^2 - 2$ $f(0) = 0 - 0 - 2$ $f(0) = -2$

2. $f(1)$: $f(1) = 1^3 - 3 \cdot 1^2 - 2$ $f(1) = 1 - 3 - 2$ $f(1) = -4$

3. $f(-3)$: $f(-3) = (-3)^3 - 3 \cdot (-3)^2 - 2$ $f(-3) = -27 - 3 \cdot 9 - 2$ $f(-3) = -27 - 27 - 2$ $f(-3) = -56$

4. $f(5)$: $f(5) = 5^3 - 3 \cdot 5^2 - 2$ $f(5) = 125 - 3 \cdot 25 - 2$ $f(5) = 125 - 75 - 2$ $f(5) = 48$

So, the values of the function for the given inputs are: $f(0) = -2$ $f(1) = -4$ $f(-3) = -56$ $f(5) = 48$