Question

X-2/7*(2x-3)+5-4x/3=0

Answer 1

$x - \frac{2}{7} \times (2x - 3) + 5 - \frac{4x}{3} = 0$
Раскрываем скобки, и умножаем выражение на
$- \frac{2}{7}$
$x - \frac{4}{7} x + \frac{6}{7} + 5 - \frac{4x}{3} = 0$
Теперь надо вычислить это выражение
$x - \frac{4}{7} x + \frac{41}{7} - \frac{4x}{3} = 0$
Теперь надо умножить обе части на 21
$21x - 12x + 123 - 28x = 0$
Теперь надо привести подобные члены
$- 19x + 123 = 0$
Перенести число без x в правую часть равенства
$- 19x = - 123$
Разделить обе части на - 19
$x = \frac{123}{19}$
Ответ:
$\frac{123}{19}$

Answer 2

To solve the equation $\frac{X-2}{7} \times (2x-3) + \frac{5-4x}{3} = 0$, we need to find the value of $X$ that satisfies the equation. Let's simplify and solve it step by step:

Step 1: Distribute the terms

$\frac{X-2}{7} \times (2x-3) + \frac{5-4x}{3} = 0$

$\frac{2xX-3X-4x+6}{7} + \frac{5-4x}{3} = 0$

Step 2: Combine the fractions by finding a common denominator. The common denominator is 7 times 3, which is 21.

$\frac{(2xX-3X-4x+6) \times 3 + (5-4x) \times 7}{21} = 0$

$\frac{6xX-9X-12x+18+35-28x}{21} = 0$

Step 3: Combine like terms

$\frac{6xX-12x-9X-28x+53+18}{21} = 0$

Step 4: Combine $X$ terms and constant terms

$\frac{(6xX-9X)-12x-28x+53+18}{21} = 0$

$\frac{X(6x-9)-40x+71}{21} = 0$

Step 5: Now, we want to isolate $X$ on one side of the equation. First, let's get rid of the fraction by multiplying both sides by 21:

$21 \times \left( \frac{X(6x-9)-40x+71}{21} \right) = 0$

$X(6x-9) - 40x + 71 = 0$

Step 6: Now, let's solve for $X$:

$X(6x-9) = 40x - 71$

$X = \frac{40x - 71}{6x - 9}$

This is the simplified expression for $X$ in terms of $x$. If you have a specific value for $x$, you can substitute it into this expression to find the corresponding value of $X$.