Question

Дана функция f(x)=x3-3x2+1. Найдите f(0),f(-1)

Answer 1

Дана функция f(x)=x3-3x2+1. Найдите f(0),f(-1)

f(0)=0³-3*0²+1=0-0+1=1

f(-1)=(-1)³-3*(-1)²+1=-1-3+1=-3

Answer 2

To find the values of the function f(x) = x^3 - 3x^2 + 1 at specific points, simply substitute the given values of x into the function.

1. f(0): f(0) = 0^3 - 3 * 0^2 + 1 f(0) = 0 - 0 + 1 f(0) = 1

2. f(-1): f(-1) = (-1)^3 - 3 * (-1)^2 + 1 f(-1) = -1 - 3 * 1 + 1 f(-1) = -1 - 3 + 1 f(-1) = -3

So, the values of the function f(x) at x = 0 and x = -1 are f(0) = 1 and f(-1) = -3, respectively.