Question

4(2+x) < 3x + 8 - решение

Answer 1

$8 + 4x < 3x + 8 \\ 4x - 3x < 8 - 8 \\ x < 0 \\ x \in ( - \infty \: k \: 0)$
вместо k - ;

Answer 2

To solve the inequality 4(2 + x) < 3x + 8, follow these steps:

Step 1: Distribute the 4 on the left side of the inequality:

4(2 + x) = 8 + 4x

Step 2: Now the inequality becomes:

8 + 4x < 3x + 8

Step 3: Subtract 3x from both sides to isolate the variable term on one side of the inequality:

8 + 4x - 3x < 3x + 8 - 3x

This simplifies to:

8 + x < 8

Step 4: Now, subtract 8 from both sides to isolate the variable term:

8 + x - 8 < 8 - 8

This simplifies to:

x < 0

The solution to the inequality is x < 0.