Question

Расположите в порядке числа a,b,c если a×12=b×9=c×10????

Answer 1

В порядке чего?
если возрастания, то acb
если уменьшения, то bca


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Answer 2

To find the order of numbers a, b, and c, given the equation a×12=b×9=c×10, we can solve for the ratios of these numbers. Let's find the values of a/b and b/c:

a × 12 = b × 9 (Divide both sides by b) a/b = 9/12 = 3/4

b × 9 = c × 10 (Divide both sides by c) b/c = 10/9

Now, we can compare these ratios:

a/b = 3/4 b/c = 10/9

Since a/b = 3/4, and b/c = 10/9, we can rewrite the ratios in terms of a, b, and c:

a = (3/4) b c = (9/10) b

Now we can choose an arbitrary value for b, and then find the corresponding values for a and c. Let's say b = 40 (it could be any positive value, but for simplicity, let's choose 40).

a = (3/4) * 40 = 30 c = (9/10) * 40 = 36

So the order of the numbers from least to greatest is: a = 30, b = 40, c = 36.