
Sqrt3 ctg(п/4-x)=1!!!!!


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To solve the equation, we need to find the value of the angle "x" that satisfies the equation:
√3 * cot(π/4 - x) = 1
First, let's simplify the left-hand side of the equation:
cot(π/4 - x) = 1/√3
Now, we need to find the angle "x" that satisfies this simplified equation. To do that, we can use the definition of the cotangent function:
cot(θ) = 1/tan(θ)
So, we can rewrite the equation as:
1/tan(π/4 - x) = 1/√3
Now, we need to find the angle whose tangent is equal to √3. The tangent of π/6 (30 degrees) is √3. Therefore, π/4 - x must be equal to π/6:
π/4 - x = π/6
Now, solve for "x":
x = π/4 - π/6
To simplify, find a common denominator:
x = (3π/12) - (2π/12)
x = (π/12)
So, the solution to the equation is:
x = π/12
Note: The equation was solved for real values of "x." However, trigonometric functions have periodicity, so there are infinitely many solutions for "x" in the real numbers. For example, you can add any multiple of 2π to the solution, and it will still satisfy the equation.


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