Question

14(3х-15)=252 7(х-5)=63

Answer 1

42х-210=252
42х=252+210
42х=462
х=462÷42
х=11

Ответ: х=11

→выберете этот ответ как лучший пожалуйста)

Answer 2

$7(x - 5) = 63 \\ 7x - 35 = 63 \\ 7x = 63 + 35 \\ 7x = 98 \\ x = 14$

$14(3x - 15) = 252 \\ 42x - 210 = 252 \\ 42x = 252 + 210 \\ 42x = 462 \\ x = 11$

Answer 3

To solve the equations, we need to find the value of 'x' that satisfies each equation. Let's solve them step by step:

1. 14(3x - 15) = 252

First, distribute the 14 on the left side:

42x - 210 = 252

Next, move the constant term (-210) to the right side by adding 210 to both sides:

42x = 252 + 210 42x = 462

Finally, solve for 'x' by dividing both sides by 42:

x = 462 / 42 x = 11

So, the value of 'x' that satisfies the first equation is x = 11.

2. 7(x - 5) = 63

First, distribute the 7 on the left side:

7x - 35 = 63

Next, move the constant term (-35) to the right side by adding 35 to both sides:

7x = 63 + 35 7x = 98

Finally, solve for 'x' by dividing both sides by 7:

x = 98 / 7 x = 14

So, the value of 'x' that satisfies the second equation is x = 14.

Therefore, the solutions to the given equations are x = 11 and x = 14.