Question

(1-х)(2+х)+(3+х)(4+х)

Answer 1

(1-х)(2+х)+(3+х)(4+х)
2+х-2х-х^2+12+3х+4х+х^2
2+х-2х+12+3х+4х
14-2х+8х
14+6х

Answer 2

Ответ:

14+6х

Пошаговое объяснение:

(1-х)(2+х)+(3+х)(4+х)

2+х-2х-х^2+12+3х+4х+х^2

2+х-2х+12+3х+4х

14-2х+8х

14+6х

Answer 3

To simplify the given expression, follow the order of operations (PEMDAS/BODMAS):

1. Start with the terms inside the parentheses: (1 - x)(2 + x) + (3 + x)(4 + x)

2. Multiply the terms inside the first set of parentheses: (2 - 2x + x - x^2) + (3 + x)(4 + x)

3. Simplify the terms inside the second set of parentheses: (2 - 2x + x - x^2) + (12 + 7x + x^2)

4. Now, combine like terms from both sets of parentheses: 2 - 2x + x - x^2 + 12 + 7x + x^2

5. Simplify further by combining like terms: (2 + 12) + (-2x + x + 7x) + (x^2 - x^2)

6. Continue simplifying: 14 + 6x + 0

7. The final simplified expression is: 14 + 6x