Question

Sin L = 0,6; L – угол 2 четверти. Найдите cosL.

Answer 1

Sinл во второй четверти имеет знак +( положительный ) косинус отрицательный соответственно
cosl=-√1-sinl^2 = -0.8

Answer 2

To find the value of cos(L), we need to first identify the quadrant in which angle L lies. The information given states that L is an angle in the second quadrant, and its sine value is 0.6. In the second quadrant, the sine value is positive, and the cosine value is negative.

Now, we can use the trigonometric identity relating the sine and cosine of an angle in a right triangle:

sin^2(L) + cos^2(L) = 1

Since we know the value of sin(L) is 0.6, we can plug it into the equation:

0.6^2 + cos^2(L) = 1

0.36 + cos^2(L) = 1

Now, let's solve for cos^2(L):

cos^2(L) = 1 - 0.36

cos^2(L) = 0.64

Finally, to find the value of cos(L), we take the square root of both sides (remembering that cos(L) is negative in the second quadrant):

cos(L) = -√0.64

cos(L) = -0.8

So, the value of cos(L) is -0.8.