Question

8+3b=-7+2b -3d-10=3d-6

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

To solve the system of equations, we'll start by isolating the variables on one side of the equation.

1. 8 + 3b = -7 + 2b

First, let's move all the b terms to one side of the equation by subtracting 2b from both sides:

8 + 3b - 2b = -7 + 2b - 2b

This simplifies to:

8 + b = -7

Next, let's isolate b by subtracting 8 from both sides:

b = -7 - 8

b = -15

So, the value of b is -15.

2. -3d - 10 = 3d - 6

Let's move all the d terms to one side of the equation. To do that, we can add 3d to both sides:

-3d - 10 + 3d = 3d - 6 + 3d

The -3d and +3d on the left side cancel each other out, and on the right side, we have:

-10 = 6d - 6

Now, let's isolate d by adding 6 to both sides:

-10 + 6 = 6d - 6 + 6

-4 = 6d

Finally, divide both sides by 6 to solve for d:

d = -4/6

Simplified, d = -2/3.

So, the values of the variables are: b = -15 d = -2/3