Question

Log2(1-3x)меньше или равно 4

Answer 1

Ответ:меньше

Пошаговое объяснение:

Answer 2

To determine the values of 'x' for which log2(1-3x) is less than or equal to 4, we need to solve the inequality:

log2(1-3x) ≤ 4

First, let's recall the properties of logarithms. The inequality can be rewritten in exponential form as follows:

2^4 ≥ 1-3x

16 ≥ 1-3x

Next, isolate the variable 'x' by moving the constant term to the other side:

16 - 1 ≥ -3x

15 ≥ -3x

Now, divide both sides by -3, and remember to reverse the inequality when dividing by a negative number:

-5 ≤ x

So, the solution to the inequality is: x ≤ -5.