Question

2sin^2x-1=...............​

Answer 1

Ответ:

Пошаговое объяснение:

2sin^2x - 1 = 2sin^2x - (sin^2x + cos^2x) = 2sin^2x - sin^2x - cos^2x =

= sin^2x - cos^2x = - (cos^2x - sin^2x) = - cos2x

Answer 2

To simplify the expression 2sin^2(x) - 1, we can use the trigonometric identity:

sin^2(x) + cos^2(x) = 1

Rearranging this identity, we get:

sin^2(x) = 1 - cos^2(x)

Now, substitute sin^2(x) with 1 - cos^2(x) in the original expression:

2sin^2(x) - 1 = 2(1 - cos^2(x)) - 1

Distribute the 2:

2(1 - cos^2(x)) - 1 = 2 - 2cos^2(x) - 1

Combine like terms:

2 - 2cos^2(x) - 1 = 1 - 2cos^2(x)

So, the simplified expression is:

2sin^2(x) - 1 = 1 - 2cos^2(x)