Question

Найдите производную функцию y= in 8x

Answer 1

Ответ:

1/8x*2=1/4x

Пошаговое объяснение:

Answer 2

It seems like there might be a typo in the provided function. If you meant to write "y = √(8x)" where √ represents the square root, then I can proceed to find its derivative. If not, please clarify the function, and I'll be happy to help you with the differentiation.

Assuming the function is y = √(8x), we can find its derivative using the chain rule:

Let u = 8x, then y = √u

Now, we can find dy/dx:

dy/dx = d(√u)/du * du/dx

First, find d(√u)/du:

d(√u)/du = (1/2) * u^(-1/2)

Next, find du/dx:

du/dx = d(8x)/dx = 8 * d(x)/dx = 8 * 1 = 8

Now, combine the results:

dy/dx = d(√u)/du * du/dx dy/dx = (1/2) * u^(-1/2) * 8 dy/dx = 4 * u^(-1/2)

Finally, substitute back u = 8x:

dy/dx = 4 * (8x)^(-1/2)

Simplify further:

dy/dx = 4 * √(1/8x)

So, the derivative of the function y = √(8x) with respect to x is dy/dx = 4 * √(1/8x).