Question

1)2х²-8х+11=0 2)16х²-8х+1=0​

Answer 1

1) нет решения

2)D=64-64=0

X1= - b/2a

X=8/32

X=0,25

Answer 2

Ответ:

1.) Решения нет.

2.) 0,25

Пошаговое объяснение:

1) D = -8(квадрат) - 4*2*11 = 64 - 88 = -24 (решения в данном случае нет, так как получилось меньше нуля)

Ответ: Решения нет

2) D = -8(квадрат) - 4*16*1 = 64 - 64 = 0 (здесь будет только один корень, так как равен нулю)

-(-8)+0/2*16 = 8/32 = 0,25

Ответ: 0,25

Answer 3

To solve the given quadratic equations, we can use the quadratic formula. The quadratic formula is given by:

For the equation ax² + bx + c = 0, the solutions for x are:

x = (-b ± √(b² - 4ac)) / 2a

Let's solve each equation step by step:

1. 2x² - 8x + 11 = 0

Here, a = 2, b = -8, and c = 11.

x = (-(-8) ± √((-8)² - 4 * 2 * 11)) / (2 * 2) x = (8 ± √(64 - 88)) / 4 x = (8 ± √(-24)) / 4

Since the discriminant (b² - 4ac) is negative, the equation has no real solutions. The solutions are complex numbers:

x = (8 + √24i) / 4 and x = (8 - √24i) / 4 where i is the imaginary unit, i² = -1.

2. 16x² - 8x + 1 = 0

Here, a = 16, b = -8, and c = 1.

x = (-(-8) ± √((-8)² - 4 * 16 * 1)) / (2 * 16) x = (8 ± √(64 - 64)) / 32 x = (8 ± √0) / 32

Since the discriminant is zero, the equation has only one real solution:

x = 8 / 32 x = 1 / 4

So, the solutions for the second equation are real and equal to x = 1/4.