Question

Log2(x^2-3x)=2 как его решить​

Answer 1

Вот что у меня вышло.

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Answer 2

To solve the equation log2(x^2 - 3x) = 2, we'll follow these steps:

Step 1: Rewrite the equation in exponential form. Step 2: Solve for x.

Step 1: Rewrite the equation in exponential form. In logarithmic form, the equation log2(x^2 - 3x) = 2 can be expressed as: 2^2 = x^2 - 3x

Step 2: Solve for x. Now, we have a quadratic equation: x^2 - 3x - 4 = 0.

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

where a = 1, b = -3, and c = -4.

x = (3 ± √((-3)^2 - 4 * 1 * -4)) / 2 * 1 x = (3 ± √(9 + 16)) / 2 x = (3 ± √25) / 2 x = (3 ± 5) / 2

Now, we have two possible solutions for x:

1. x = (3 + 5) / 2 x = 8 / 2 x = 4

2. x = (3 - 5) / 2 x = -2 / 2 x = -1

So, the two solutions for the equation log2(x^2 - 3x) = 2 are x = 4 and x = -1.