Question

(х-10) (х+10) (4-а) (4+а) (7х-1) (7х+1) (8а-3b) (8a+3b)

Answer 1

Х²-100

16-а²

49х²-1

64а²-9b²

Answer 2

It seems like you want to simplify the given expressions. To do that, let's multiply the terms together and then simplify wherever possible:

1. (х-10)(х+10) = x^2 - 10x + 10x - 100 (using the FOIL method) = x^2 - 100

2. (4-а)(4+а) = 4^2 - а^2 (using the difference of squares formula) = 16 - а^2

3. (7х-1)(7х+1) = 7x^2 + 7x - 7x - 1 (using the FOIL method) = 7x^2 - 1

4. (8а-3b)(8а+3b) = 8a^2 + 8а3b - 3b8а - 3b3b (using the FOIL method) = 8a^2 + 24ab - 9b^2

So, the simplified expressions are:

1. (х-10)(х+10) = x^2 - 100
2. (4-а)(4+а) = 16 - а^2
3. (7х-1)(7х+1) = 7x^2 - 1
4. (8а-3b)(8а+3b) = 8a^2 + 24ab - 9b^2