Question

1) 6х-4у=36 2) 3х+у=12 3) 15у-20х=60 4)2х-у=4

Answer 1

Надеюсь так надо. Последнее скину не могу. Нельзя

Answer 2

To solve this system of equations, we'll use the method of substitution or elimination. I'll use the elimination method here. The goal is to eliminate one variable and then solve for the remaining variable.

Let's write down the given equations:

1. 6x - 4y = 36
2. 3x + y = 12
3. 15y - 20x = 60
4. 2x - y = 4

Step 1: Let's start by eliminating y from equations (1) and (2):

Multiply equation (2) by 4 so that the coefficient of y becomes -4, and then add the resulting equation to equation (1):

4(3x + y) = 4(12) => 12x + 4y = 48

Now add the two equations: (6x - 4y) + (12x + 4y) = 36 + 48 18x = 84

Step 2: Now, solve for x: x = 84 / 18 x = 4.6667 (rounded to four decimal places)

Step 3: Now that we have the value of x, let's find the value of y. We can use equation (2) for this purpose:

3x + y = 12 3(4.6667) + y = 12 14 + y = 12 y = 12 - 14 y = -2

So, the solution to the system of equations is: x = 4.6667 (approximately) y = -2