Question

Решите системы уравнений способом подстановки: {у+4х=12 {2х-3у=-22 методом сложения: {4х+3у=-4 {6х+5у=-7​ Посмотреть ответы binamaksimchuk binamaksimchuk Ответ: Пошаговое объяснение: {у+4х=12 {2х-3у=-22 у=12-4х 2х-3(12-4х)= -22 2х-36+12х= -22 14х= -22+36 14х=14 х=14:14 х=1 у=12-4*1 у=8 Ответ:(1;8) {4х+3у= -4   *(-3) {6х+5у= -7​     *2 -12х-9у= 12 12х+10у= -14       у= -2 4х+3*(-2)= -4 4х-6= -4 4х= -4+6 4х=2 х=2:4 х=0,5 Ответ:(0,5;-2) Участник Знаний Участник Знаний Ответ: Пошаговое объяснение: 1) {у+4х=12 {2х-3у=-22 {у=12-4х {2х-3(12-4х)=-22 {у=12-4х {2х-36+12х=-22 {у=12-4х 14х=-22+36 {у=12-4х {14х=14 {у=12-4х {х=14/14 {у=12-4х {х=1 Подставляем значение х в первое уравнение у=12-4*1 у=12-4 у=8 Ответ: (1;8) 2) {4х+3у=-4 умножаем на (-5) {6х+5у=-7 умножаем на 3 {-20х-15у=20 {18х+15у=-21 Метод алгебраического сложения -20х+18х-15у+15у=20+(-21) -2х=-1 х=1/2 Подставляем значение х в одно из уравнений 6х+5у=-7 6*1/2+5у=-7 3+5у=-7 5у=-7-3 5у=-10 у=-10/5 у=-2 Ответ: (1/2;-2) Новые вопросы в Математика За 6 год робітник виготовляє 54 деталі. Скільки деталей виготовить робітник за 9 годин? помогите пожалуйста решить​ разность двух чисел равна 48, причем одно число в 4 раза больше другого. Чему равно большее из чисел? Пожалуйста помогите!!!!!! Очень срочно нужно помогите пожалуйста Спростіть вираз і обчисліть значення виразу 0,13*р+0,47*р,якщо р=0,14 Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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true; }

Answer 1

Давайте решим обе системы уравнений сначала методом подстановки, а затем методом сложения.

Первая система уравнений:

1. у + 4х = 12
2. 2х - 3у = -22

Сначала решим первое уравнение относительно y:

1. у = 12 - 4х

Подставим это значение у во второе уравнение: 2х - 3(12 - 4х) = -22 2х - 36 + 12х = -22 14х = 14 х = 14 / 14 х = 1

Теперь найдем у, используя уравнение у = 12 - 4х: у = 12 - 4 * 1 у = 8

Итак, решение первой системы уравнений: (х, у) = (1, 8).

Вторая система уравнений:

1. 4х + 3у = -4
2. 6х + 5у = -7

Мы можем умножить первое уравнение на -3 и второе уравнение на 2, чтобы избавиться от y при сложении: -3 * (4х + 3у) = -3 * (-4) 2 * (6х + 5у) = 2 * (-7)

-12х - 9у = 12 12х + 10у = -14

Сложим оба уравнения: -12х - 9у + 12х + 10у = 12 - 14 у = -2

Теперь подставим значение у в одно из исходных уравнений (для удобства, выберем первое): 4х + 3 * (-2) = -4 4х - 6 = -4 4х = -4 + 6 4х = 2 х = 2 / 4 х = 0.5

Итак, решение второй системы уравнений: (х, у) = (0.5, -2).

Таким образом, решения систем уравнений:

1. (х, у) = (1, 8)
2. (х, у) = (0.5, -2).