Question

11*11=4 22*22=16 33*33=? С объяснением пж

Answer 1

Ответ:

36

Пошаговое объяснение:

11*11=(1+1)*(1+1)=2*2=4

22*22=(2+2)*(2+2)=4*4=16

33*33=(3+3)*(3+3)=6*6=36

Answer 2

The given examples suggest a pattern where the product of two identical two-digit numbers is equal to the square of the tens digit. However, this pattern does not hold true for all cases. Let's examine it further:

In the first example, 11 * 11 = 121. The tens digit of 11 is 1, and 1^2 = 1, which matches the result.

In the second example, 22 * 22 = 484. The tens digit of 22 is 2, and 2^2 = 4, which matches the result.

Now, let's apply the same pattern to the third example, 33 * 33. The tens digit of 33 is 3, so according to the pattern, we would expect the result to be 3^2 = 9. However, that is not the case.

In reality, 33 * 33 = 1089, which does not follow the pattern observed in the previous examples. Therefore, we can conclude that the pattern does not apply consistently to all cases, and in this particular example, 33 * 33 is equal to 1089.