Question

(0,1x + 0,01y = 32,(2x + y = 1200;​

Answer 1

Пошаговое объяснение:

×+0,1у=320 ×=320-0,1у

2*(320-0,1у)+у=1200 (*10 и раскроем скобкм

6400-2у+10у=12000 8у=5600 у=700

×=320-70 ×=250

Answer 2

It looks like you've provided a system of two linear equations with two variables. The system can be written as:

Equation 1: 0.1x + 0.01y = 32 Equation 2: 2x + y = 1200

To solve this system of equations, you can use various methods such as substitution, elimination, or graphical methods. I'll solve it using the substitution method.

Let's start by solving Equation 1 for one of the variables. I'll solve it for y:

0.1x + 0.01y = 32 0.01y = 32 - 0.1x y = (32 - 0.1x) / 0.01 y = 3200 - 10x

Now we can substitute this expression for y into Equation 2:

2x + y = 1200 2x + (3200 - 10x) = 1200 2x + 3200 - 10x = 1200 -8x + 3200 = 1200 -8x = 1200 - 3200 -8x = -2000 x = -2000 / -8 x = 250

Now that we have the value of x, we can substitute it back into the expression for y:

y = 3200 - 10x y = 3200 - 10(250) y = 3200 - 2500 y = 700

So, the solution to the system of equations is x = 250 and y = 700.