Question

1/3÷x=-3/9. 2/7x=-5/14. (x+3)(x-4)=0

Answer 1

Ответ:

1) х=0

2) х=-1/14

3)х=-6

Пошаговое объяснение:

1)х= 1/3-3/9

х= 0

1/3-3/9=3/9-3/9=0

2) х=2/7-5/14

х=-1/14

2/7-5/14=4/14-5/14=-1/14

3) 2х-12=0

2х=-12

х=(-12):2

х=-6

Answer 2

To solve the equations, let's go through them one by one:

1. 1/3÷x = -3/9

To divide by a fraction, we can multiply by its reciprocal. So, we have:

(1/3) * (1/x) = -3/9

1/3x = -3/9

To eliminate the fractions, we can multiply both sides of the equation by the least common multiple (LCM) of the denominators, which is 9:

9 * (1/3x) = 9 * (-3/9)

3/x = -1

Now, we can cross-multiply:

3 = -x

Dividing both sides by -1, we get:

x = -3

2. (2/7)x = -5/14

To eliminate the fraction, we can multiply both sides of the equation by the reciprocal of (2/7), which is (7/2):

(7/2) * (2/7)x = (7/2) * (-5/14)

x = -35/28

Simplifying the fraction, we have:

x = -5/4

3. (x+3)(x-4) = 0

To solve this quadratic equation, we can set each factor equal to zero:

x + 3 = 0 or x - 4 = 0

Solving the first equation:

x = -3

Solving the second equation:

x = 4

Therefore, the solutions to the equation (x+3)(x-4) = 0 are x = -3 and x = 4.