Question

-(3-c)+(13-15c)=2(3-2c)-6c

Answer 1

Ответ:

С=1

Пошаговое объяснение:

Answer 2

Ответ:

-(3-c)+(13-15c)=2(3-2c)-6c

-3+c+13-15c=6-4c

c-15c+4c=6+3-13

-10c=22

c=22÷10

c=2,2

Answer 3

Let's solve the given equation step by step:

-(3 - c) + (13 - 15c) = 2(3 - 2c) - 6c

First, distribute the constants and variables within the parentheses:

-3 + c + 13 - 15c = 6 - 4c - 6c

Combine like terms on both sides of the equation:

-2 + c - 15c = 6 - 10c

Now, combine the constants and the "c" terms separately:

c - 15c = -2 - 10c + 6

Simplify further:

-14c = 4 - 10c

Add 10c to both sides:

-14c + 10c = 4

Simplify:

-4c = 4

Now, divide both sides by -4:

c = -1

So, the solution to the given equation is c = -1.