Question

Cos(п/4-b)+cos(п/4+b)

Answer 1

Ответ:

sqrt2×cos(b)

Пошаговое объяснение:

Answer 2

The expression you've provided involves trigonometric functions. Let's simplify it step by step:

We have: cos(π/4 - b) + cos(π/4 + b)

Using the sum-to-product trigonometric identity: cos(A) + cos(B) = 2 * cos((A + B) / 2) * cos((A - B) / 2)

In this case, A = π/4 - b and B = π/4 + b:

cos(π/4 - b) + cos(π/4 + b) = 2 * cos((π/4 - b + π/4 + b) / 2) * cos((π/4 - b - π/4 - b) / 2)

Simplifying: = 2 * cos(π/2) * cos(-b)

Since cos(π/2) = 0 and cos(-b) = cos(b), the expression becomes: = 0

So, the simplified result of the expression cos(π/4 - b) + cos(π/4 + b) is 0.