Question

4х^2-6х+8+10х+8-6х^2=2

Answer 1

Відповідь:

4х^2-6х+8+10х+8-6х^2=2

4х^2-6х+8+10х+8-6х^2-2=0

х^2-4х+14=0

х1=1-2&2

х2=1+2&2

& - корінь)

Answer 2

To solve the equation 4x^2 - 6x + 8 + 10x + 8 - 6x^2 = 2, we can start by combining like terms:

-6x^2 + 4x^2 - 6x + 10x + 8 + 8 = 2

This simplifies to:

-2x^2 + 4x + 16 = 2

Next, let's move all the terms to one side of the equation to set it equal to zero:

-2x^2 + 4x + 16 - 2 = 0

Simplifying further:

-2x^2 + 4x + 14 = 0

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Here, a = -2, b = 4, and c = 14. Substituting these values into the quadratic formula:

x = (-4 ± √(4^2 - 4(-2)(14))) / (2(-2)) x = (-4 ± √(16 + 112)) / (-4) x = (-4 ± √128) / (-4)

Simplifying the square root:

x = (-4 ± √(64 * 2)) / (-4) x = (-4 ± 8√2) / (-4)

Now, we can simplify further and write the two solutions:

x1 = (-4 + 8√2) / (-4) x2 = (-4 - 8√2) / (-4)

Simplifying the fractions:

x1 = (4 - 8√2) / 4 x2 = (4 + 8√2) / 4

Simplifying:

x1 = 1 - 2√2 x2 = 1 + 2√2

So the solutions to the equation 4x^2 - 6x + 8 + 10x + 8 - 6x^2 = 2 are x = 1 - 2√2 and x = 1 + 2√2.