Question

(x^2+1)(18x-17)(29-30x)​

Answer 1

Ответ:

- 540х⁴ + 1032х³ - 1033х² + 1032х - 494

Пошаговое объяснение:

(x²+1)(18x-17)(29-30x)

Перемножаем первую и вторую скобку:

( 18х³ - 17х² + 18х - 17 ) × ( 29 - 30х )

Перемножаем скобки:

522х³ - 540х⁴ - 493х² + 510х³ + 522х - 540х² - 490 + 510х

Упрощаем:

- 540х⁴ + 1032х³ - 1033х² + 1032х - 494

Answer 2

It looks like you've provided a polynomial expression: $(x^2+1)(18x-17)(29-30x)$. To proceed, you can expand this expression by using the distributive property. Here's the expanded form of the expression:

$(x^2+1)(18x-17)(29-30x)$

First, expand the first two factors: $(x^2+1)(18x-17)$

$(x^2+1)(18x-17) = x^2 \cdot 18x + x^2 \cdot (-17) + 1 \cdot 18x - 1 \cdot 17$ $= 18x^3 - 17x^2 + 18x - 17$

Now, multiply the result by the third factor: $(18x^3 - 17x^2 + 18x - 17)(29-30x)$

To do this multiplication, distribute each term in the first factor to each term in the second factor and then combine like terms:

$$\begin{align*} & (18x^3 - 17x^2 + 18x - 17)(29-30x) \\ = & 18x^3 \cdot 29 - 18x^3 \cdot 30x - 17x^2 \cdot 29 + 17x^2 \cdot 30x + 18x \cdot 29 - 18x \cdot 30x - 17 \cdot 29 + 17 \cdot 30x \\ = & 522x^3 - 540x^4 - 493x^2 + 510x^3 + 522x - 540x^2 - 493 + 510x \\ = & -540x^4 + 1032x^3 - 1033x^2 + 1032x - 493 \end{align*}$$

So, the expanded form of the expression $(x^2+1)(18x-17)(29-30x)$ is $-540x^4 + 1032x^3 - 1033x^2 + 1032x - 493$.