Question

5(х-4)= 15(а-у)= 9(2х+4)= 5(10-х)= 7(3у+4)= 4(2+х+3у)=

Answer 1

5х-20
18х+36
50-5х
21у+28

Answer 2

It seems like you've provided a list of equations with variables. Let's solve each equation step by step:

1. $5(x-4)$

   Distribute the 5: $5x - 20$

2. $15(a-u)$

   Distribute the 15: $15a - 15u$

3. $9(2x+4)$

   Distribute the 9: $18x + 36$

4. $5(10-x)$

   Distribute the 5: $50 - 5x$

5. $7(3u+4)$

   Distribute the 7: $21u + 28$

6. $4(2+x+3u)$

   Distribute the 4: $8 + 4x + 12u$

So, the simplified forms of the given equations are:

1. $5(x-4) = 5x - 20$
2. $15(a-u) = 15a - 15u$
3. $9(2x+4) = 18x + 36$
4. $5(10-x) = 50 - 5x$
5. $7(3u+4) = 21u + 28$
6. $4(2+x+3u) = 8 + 4x + 12u$

Please let me know if you need any further assistance!