Question

(4x-5)(3x+7)-(x-2)(4x+2)=33x-9

Answer 1

Ответ:

$x_{1}$=-1

$x_{2}$=2,75

Пошаговое объяснение:

(4x-5)(3x+7)-(x-2)(4x+2)=33x-9

12$x^{2}$+28x-15x-35-(4$x^{2}$+2x-8x-4)=33x-9

12$x^{2}$+28x-15x-35-(4$x^{2}$-6x-4)=33x-9

12$x^{2}$+28x-15x-35-4$x^{2}$+6x+4=33x-9

8$x^{2}$+19x-31=33x-9

8$x^{2}$+19x-31-33x+9=0

8$x^{2}$-14x-22=0

4$x^{2}$-7x-11=0

-7x=4x-11x

4$x^{2}$-4x-11x-11=0

4x(x+1)-11(x+1)=0

(x+1)(4x-11)=0

x+1=0

$x_{1}$=-1

4x-11=0

$x_{2}$=$\frac{11}{4}$=2,75

Answer 2

Let's simplify the expression step by step:

(4x - 5)(3x + 7) - (x - 2)(4x + 2)

Expanding the first set of parentheses:

= (12x^2 + 28x - 15x - 35) - (x - 2)(4x + 2)

= 12x^2 + 28x - 15x - 35 - (x - 2)(4x + 2)

Expanding the second set of parentheses:

= 12x^2 + 28x - 15x - 35 - (4x^2 + 2x - 8x - 4)

= 12x^2 + 28x - 15x - 35 - 4x^2 - 2x + 8x + 4

Combining like terms:

= (12x^2 - 4x^2) + (28x - 15x - 2x + 8x) + (-35 + 4)

= 8x^2 + 19x - 31

The simplified expression is 8x^2 + 19x - 31, which is not equal to 33x - 9. Therefore, there seems to be an error in the initial statement.