Question

Y=sin x, (Pi/4)<=x<= (5Pi/3), y=0

Answer 1

Ответ :
Объяснение : на рисунке

Answer 2

It seems like you've provided a piecewise function involving the sine function and a specific range of values for x. Let's break down what you've mentioned:

1. Function: $y = \sin(x)$
2. Range for $x$: $\frac{\pi}{4} \leq x \leq \frac{5\pi}{3}$
3. Condition: $y = 0$

In this scenario, the function $y = \sin(x)$ represents a sine wave, which oscillates between -1 and 1 as $x$ changes. The given range for $x$, $\frac{\pi}{4} \leq x \leq \frac{5\pi}{3}$, indicates that you're interested in values of $x$ between $\frac{\pi}{4}$ (approximately 0.785) and $\frac{5\pi}{3}$ (approximately 5.236).

However, you also mentioned the condition $y = 0$, which indicates that you want to find the values of $x$ within the specified range where the function $y = \sin(x)$ equals 0.

The sine function $\sin(x)$ equals 0 at specific values of $x$ such as $0, \pi, 2\pi, 3\pi, \ldots$. These are the points where the sine curve crosses the x-axis.

In the given range $\frac{\pi}{4} \leq x \leq \frac{5\pi}{3}$, there are two points where $\sin(x)$ equals 0:

1. $x = \pi$ (since $\pi$ falls within the specified range)
2. $x = 2\pi$ (since $2\pi$ also falls within the specified range)

So, within the range $\frac{\pi}{4} \leq x \leq \frac{5\pi}{3}$, the values of $x$ where $y = \sin(x)$ equals 0 are $x = \pi$ and $x = 2\pi$.

If you're looking for more specific information or calculations, feel free to ask!