Question

3) 7(2x+9)+3x = 114;4) 3(4x+13)–25 = 74.​

Answer 1

7(2х+9)+3х = 114

14х+63+3х = 114

17х = 51

х = 51/17 = 3

3(4х+13)-25 = 74

12х+39-25 = 74

12х = 74-39+25

12х = 60

х = 60/12 = 5

Answer 2

It looks like you have provided two equations involving variables (x) that need to be solved for. Let's solve them step by step.

Equation 1: $7(2x+9)+3x = 114$

First, distribute the multiplication: $14x + 63 + 3x = 114$

Combine like terms: $17x + 63 = 114$

Subtract 63 from both sides: $17x = 51$

Divide by 17: $x = 3$

So, the solution for the first equation is $x = 3$.

Equation 2: $3(4x+13) - 25 = 74$

Distribute the multiplication: $12x + 39 - 25 = 74$

Combine like terms: $12x + 14 = 74$

Subtract 14 from both sides: $12x = 60$

Divide by 12: $x = 5$

The solution for the second equation is $x = 5$.

Therefore, the solutions for the given equations are $x = 3$ for the first equation and $x = 5$ for the second equation.