Question

(2x2 + 6x – 7) + (A – 5x) = 3x2 – 7x – 1.

Answer 1

Ответ:

4(+6х-7)+A-5x=6-7x-1

(-3+6)+A-5x=5-7x

-3+6x+A-5x=5-7x

-3+x+A=5-7x

x+7x=5+3-A

8x=8-A

x=1-1/8A

Answer 2

To solve the equation (2x^2 + 6x - 7) + (A - 5x) = 3x^2 - 7x - 1, we can start by simplifying both sides of the equation and then solving for the variable x.

Let's simplify the left side first: (2x^2 + 6x - 7) + (A - 5x) = 3x^2 - 7x - 1

Combine like terms on the left side: 2x^2 + 6x - 7 + A - 5x = 3x^2 - 7x - 1

Rearrange the terms: 2x^2 + 6x - 5x + 7 + A = 3x^2 - 7x - 1

Combine like terms again: 2x^2 + (6x - 5x) + (7 + A) = 3x^2 - 7x - 1

Simplify further: 2x^2 + x + 7 + A = 3x^2 - 7x - 1

Now, let's simplify the right side of the equation: 3x^2 - 7x - 1

This side is already simplified.

Now, equating the left and right sides of the equation, we have: 2x^2 + x + 7 + A = 3x^2 - 7x - 1

To continue solving for x, we need to know the value of A. If you provide a value for A, I can help you solve for x.