Question

3tg(-П/6)ctgП/6+sin3П/2 - 4cos П/4​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

Let's break down the expression step by step:

1. 3tg(-π/6): The term "tg" represents the tangent function. Since tangent is periodic with a period of π, we can simplify this expression by substituting -π/6 with its equivalent angle within one period, which is 11π/6: 3tg(-π/6) = 3tg(11π/6)

2. ctg(π/6): The term "ctg" represents the cotangent function. Cotangent is the reciprocal of tangent, so we can calculate it by taking the reciprocal of the tangent of the angle π/6: ctg(π/6) = 1/tg(π/6) = 1/tan(π/6)

3. sin(3π/2): The term "sin" represents the sine function. Sine is periodic with a period of 2π, so we can simplify this expression by finding the equivalent angle within one period, which is π/2: sin(3π/2) = sin(π/2)

4. cos(π/4): The term "cos" represents the cosine function. Cosine is also periodic with a period of 2π, so we can simplify this expression by finding the equivalent angle within one period, which is π/4: cos(π/4)

Now, let's substitute the simplified values back into the original expression:

3tg(11π/6) + 1/tg(π/6) + sin(π/2) - 4cos(π/4)

You can evaluate this expression by calculating the tangent and cosine values for the corresponding angles and then performing the addition and subtraction operations.